Hi Gus,

> According to http://www.meder.com/dip-relay_uk0.html
> this relay uses a 12VDC coil [ 12 ma ].  This means you will want
> drive the relay using a buffer between the PIC and the relay.
> You have many, many  choices.   Here are two.

> #1
> You can use a 2N7000 FET to buffer the PIC from the relay.
> Drive the gate of the FET from a pin from PORTA.  Use the FET to
> sink current from the relay coil.

> #2
> Use a 2N3904 transistor to  buffer the PIC from the relay.
> Drive the base of the 3904 using a 10K resistor.  Tie the emitter to
> ground and use the collector to sink current from the relay.

> Some choices that will influence your design......
> 1) How fast must the relay activate and deactivate ?
> 2) What is the relay controlling ?   [ voltage , current  and
> complex impedance ? ]
> 3) Where is power for the relay coil derived from ?

I want to switch on/off and change the rotation direction of the
electric motor PC-130SF-09400T-NR with this relay.

http://www.argus.lv/product_info.php?cPath=162_1990&products_id=39119&osCsid=c78e3f3b187ee6f4afaaf0c6a6fe0f25

So the PIC16F877A should control two electric motors with two
relay this way.

> I can send you a schematic if you wish one.
> Gus

Please, send me a schematic for both #1 and #2, or which is better
solution! And thanks!

--
Regards, Paul Chany
http://csanyi-pal.info

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