At 09:25 PM 15/10/2009, you wrote: > > Among motor types, which give the best power ( energy per unit of > > time ) to weight ratio ? > > I am not going to consider reliability as a factor. > > I am not including auxiliary items such as fuel tanks, air lines, > > cabling, etc.The misleading answer may be "high pressure gas > operated motor". > >A prime example of this is the "topping cycle" gas turbines used to >supply the propellant for the Space Shuttle main engines. These sit >"before the combustion "chambers proper in the main engines and >essentially preburn some incoming propellant. They can be highly >efficin\ent because of the high presseures they operate at. (About >4500 psi from memory).(Don't try this at home). > >The reason that this is misleading is that they are essentially a way >to transfer the gas mechanical energy into propellant mechanical >energy. All pumps are energy transferers - but a gas turbine is closer >to the basic principles than some. That said, the mass and volumetric >energy density of the power source can also be about as high as >anything else available. Hydrocarbons contain about 10 kWh/kg (or >about 36 MJ/kg). Hydrogen about 3 times that from memory. Maybe more. >Hydrogen volumetric density is low, but you asked about mass. > >Brain says that electric motor probably get best results from >permanent magnet units as no energy is used in magnetic field >production BUT field stengths have an upper limit set by best >available materials (various rare earth magnets) and if you were happy >to waste energy a wound field MAY get higher values. > >Power out is primarily a function of the amount of power you can get >into the motor :-). This is translated into creating interacting >magnetic fields. Simplistically, increasing voltage and decreasing >current will tend to allow higher energy densities as resistive losses >decrease with square of voltage, but here is a point at which other >factors take over. I doubt this is true. The field strength is dependent on ampere-turns-- if you have a fixed weight = a fixed area cross-sectional window for the windings, then the total resistance increases with the reciprocal of the square of the wire cross-sectional area, so the current must drop proportional to the wire cross sectional area to keep I^2*R power loss constant in the winding volume. When you look at ampere-turns, it's thus a wash since the number of turns increases proportional to the reciprocal of the wire cross- sectional area. That's leaving volume and RPM constant and playing with the wire size. Some of the RC model motors look to have interesting power-to-weight ratios.. a 1.8HP input (briefly, I should think) 14V motor with a ratio of 5W per gram.... I even see a 1700W unit with 10W/gram pwr-in/mass! Of course these use Neodymium rare-earth magnets to get that kind of performance. Best regards, Spehro Pefhany --"it's the network..." "The Journey is the reward" speff@interlog.com Info for manufacturers: http://www.trexon.com Embedded software/hardware/analog Info for designers: http://www.speff.com -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist