> However, given its low density and high surface area, I would also
> suspect that it would not reach a very high velocity while falling

That's what I thought. If my Applied Maths (aaah Ms Pfannkuck,
where are you now ?) memory serves me

v^2 = u^2 + 2as

v^2 = 0 + (2 x 9.81 x 3)

v = 8m/s (29kph, 18mph)

> A better example of very high G's would be dropping a billiard ball
> onto concrete

Yes, shock-absorbing deformation makes all the difference. That's
why stunt men's ankles don't come out their ears ;-)

You could use one of the other motion equations to work out what
deceleration time would apply to cause 1000G and the resulting
deformation. I'm guessing it would be some fraction of a mm


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