Marechiare wrote:
> So, may I conclude that you insist that for your circuit
>
> "perfect 0 to 5V square wave followed by the 2K,3.9K ohm
> divider, driving some capacitive load connected to ground"
>
> when we decrease divider's bottom resistor 3.9K to 3.85K, the time to
> rise the signal on the capacitor from 0V to 2.9V will decrease as per
> your statement that - the lower impedance - the higher speed of signal
> rising on that capacitor.

No, that is not what I said.


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