Marechiare wrote: > He propopsed an idea that an impedance calculated as (R1*R)/(R1+R2) > would reflect the "speed" of the signal - the lower impedance - the > higher speed. Yes. > I objected it with the example to remove the bottom > resistor, - the impedance will be higher, and the speed will be > higher. That's it, nothing more, no rules changed. Yes they have. The output will now go to 5V instead of 3.3V, which is a violation of the rule that the output must drive a 3.3V input within its spec. You clearly still haven't looked up Thevenin Equivalent. Go do that. ******************************************************************** Embed Inc, Littleton Massachusetts, http://www.embedinc.com/products (978) 742-9014. Gold level PIC consultants since 2000. -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist