>>> since it violates the abs. max. ratings of the >>> chip and thus is not a valid solution. >> >> I said: > (assuming inputs would tolerate it). > > Fine, if you wish to change the rules in the middle > of the game, you win, have fun! I don't so much > care for "Calvinball". If you stopped understanding something, this doesn't necessarily mean that rules have changed. This sub-discussion about "bottom devider's resistor" was initiated by Olin: *** >> For FET & Resistor >> Power consumption factor 5mW, thus resistor is >> 3V * 3V / 5mW = 1.8 KOhm > > Exactly. But to get the same speed, meaning same signal > impedence, you would need 1.2Kohms since > 2Kohm // 3Kohm = 1.2Kohm. *** He propopsed an idea that an impedance calculated as (R1*R)/(R1+R2) would reflect the "speed" of the signal - the lower impedance - the higher speed. I objected it with the example to remove the bottom resistor, - the impedance will be higher, and the speed will be higher. That's it, nothing more, no rules changed. Your "Calvinball" sarcasm, as for me, is not applicable here. -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist