>>> Exactly. But to get the same speed, meaning same signal
>>> impedence, you would need 1.2Kohms since
>>> 2Kohm // 3Kohm =3D 1.2Kohm.
>>
>> On rising edge I don't see how does mentioned in your calcs
>> 3Kohm divider's bottom resistor help to speed the rising.
>
> This is very basic electronics. =A0Look up something called
> "Thevenin Equivalent".

Interesting, obviously, removing the bottom resistor from the divider
would increase the speed of rising (assuming inputs would tolerate
it). But, according to your logic/formula removing the bottom resistor
would increase impedance and, thus, decrease the speed of rising.


>>> Once again, there is no inherently better approach,
>>> so please stop making it sound like yours is.
>>
>> Do you really want ME to adjust the sound? This kind of perception
>> depends on a listener, not on a speaker.
>
> I want you and everyone else to stick to good engineering practises.
> Absolute statements about one approach always being better than another w=
hen
> there are clearly tradeoffs envolved is superstition, not engineering.

Aha, I see, the problem is that I ommited the magic word "COULD". Ok,
if I had written " It COULD be much better to synch to sharp falling
edge" - would the rest hold true about FET + resistor to VERY PROBABLY
be better than the divider in many designs?

-- =

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