Does your encoder have explicit detents? If so, I think that each
detent is usually one count, not 4.

Note that encoders have a number of lines per rev and a number of
counts per rev. For a quadrature encoder, # of counts =3D 4* # of lines.

I have only worked with one encoder which had explicit detents and it
was implemented so that there was 1 count per detent (i.e., 4 detents
per line). It was a 32 line/rev encoder but there were 128 detents per
rev.

Sean


On Sun, Sep 6, 2009 at 1:21 AM, Josh Koffman<joshybear@gmail.com> wrote:
> On Sun, Sep 6, 2009 at 12:10 AM, Terry Harris<terry.harris@iname.com> wro=
te:
>> The code in the document counts all edges. There are 4 edges for a 'puls=
e'
>> on one channel. Are you sure you are not misunderstanding the datasheet
>> (and actually have a problem when you only get 3 counts?).
>
> AHA! I think you have hit the nail on the head Terry. The encoders I'm
> currently using have a tiny bit of wobble so it's possible that
> occasionally they're missing a step and that's how I get 3 counts. For
> the most part it's pretty rock solid at 4 counts, and if I turn the
> encoder slowly and carefully I can get it to do single steps (mostly -
> sometimes there's a bit of jitter).
>
> So...is there a standard way to deal with this? If I want one click to
> be one event, should I just do a counter or is there more elegant code
> that I'm just not thinking of?
>
> Thanks!
>
> Josh
> --
> A common mistake that people make when trying to design something
> completely foolproof is to underestimate the ingenuity of complete
> fools.
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