On Wed, 26 Aug 2009 12:51:34 -0400
Byron Jeff <byronjeff@clayton.edu> wrote:

> Continues and breaks only work within certain constructs.

Ok... The break would have taken you out of a for, if the if statement
were inside a for:

 for (i = 0; i < 3; i++) {
   if (a == 1) {
      printf("Before break\n");
      break;
      printf("After break\n");
   }
   else {
      printf("before break in else\n");
      break;
      printf("before break in else\n");
   }
 }

compiles ok and produces:

Before break

This is, of course, not an example of elegant programming, but could
explain why the 'break' worked.

John
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