For further reading on why you need termination http://en.wikipedia.org/wiki/Time_domain_reflectometer 'If the conductor is of a uniform impedance and properly terminated, the entire transmitted pulse will be absorbed in the far-end termination and no signal will be reflected.' Imagine what happens at a mid-point (or thereabouts) of a long, high speed communications bus - if there were a reflection of your communications signal. solarwind wrote: > I don't understand what you mean by "terminate" the two ends. I tried > to google for it, but searching for phrases involving "CAN" are > difficult. -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist