Part of code:
===============================================
FindCV:
    bcf     NOCV
    bcf     RDONLY
    xorlw   0x00              	; CV513
    btfsc   STATUS,Z
    retlw   PRIM_ADDR0
    xorlw   (0x00 ^ 0x08)      	; CV521
    btfsc   STATUS,Z
    retlw   PRIM_ADDR1
    xorlw   (0x08 ^ 0x1C)      	; CV541
    btfsc   STATUS,Z
    retlw   CVAR_29
    xorlw   (0x1C ^ 0x02)     	; CV515
    btfsc   STATUS,Z
    retlw   MAX_BRIGHT
    xorlw 	(0x02 ^ 0x03)     	; CV516
    btfsc  	STATUS,Z
    retlw 	E_CV516
    xorlw  	(0x03 ^ 0x04)    		; CV517
    btfsc 	STATUS,Z
    retlw 	E_CV517
    xorlw  	(0x04 ^ 0x05)    		; CV518
    btfsc  	STATUS,Z
    retlw  	E_CV518
    xorlw  	(0x05 ^ 0x20)    		; CV545
    btfsc 	STATUS,Z
    retlw  	E_CV545
    xorlw 	(0x20 ^ 0x21)    		; CV546
    btfsc  	STATUS,Z
    retlw 	E_CV546
    bsf    	RDONLY
    xorlw 	(0x21 ^ 0x06)    		; CV519
    btfsc  	STATUS,Z
    retlw 	MFG_VR_CODE 
===================================================
This routine is called with the actual CV value in w eg CV513=0x00 and
CV519=0x06

> -----Oorspronkelijk bericht-----
> Van: piclist-bounces@mit.edu [mailto:piclist-bounces@mit.edu] 
> Namens Olin Lathrop
> Verzonden: dinsdag 6 januari 2009 22:07
> Aan: Microcontroller discussion list - Public.
> Onderwerp: Re: [PIC] xorlw question
> 
> Harry H. Arends wrote:
> > Could someone explain this construction to me.
> > I looked in the MPASM help file but cant find a description.
> >
> >     xorlw  (0x05 ^ 0x20)    ; CV545
> 
> The "^" is documented in the manual, so I guess you're asking 
> why someone would do this?  To answer that, we need to see a 
> few more lines around this one.
> 
> 
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