You probably already found the description of XORLW so I guess you are
asking about the (0x05 ^ 0x20)... This is an expression that can be
evaluated at compile time, so the compiler will do that replacing it with
the literal. The oparator ^ is an XOR actually, but you can find the
explanation for that in the help.

Tamas


On Tue, Jan 6, 2009 at 8:50 PM, Harry H. Arends <h.arends@home.nl> wrote:

> LS,
>
> Could someone explain this construction to me.
> I looked in the MPASM help file but cant find a description.
>
>    xorlw       (0x05 ^ 0x20)           ; CV545
>
> Regards
>
> Harry
>
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-- 
Rudonix DoubleSaver
http://www.rudonix.com
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