In SX Microcontrollers, SX/B Compiler and SX-Key Tool, capdiamont wrote:

I got from the sxfaq "Please note that two other input pins are available: The RTCC pin (add an external pull-up, or pull-down resistor), and the MCLR* pin which requires special attention. If this is left floating, the SX could randomly perform resets. Therefore, it is important to pull this pin up to Vdd using a resistor (4.7 to 10 kOhm would be fine)."

also "A: When the RTCC input is not used, it is a good idea to tie it to some defined level instead of leaving it "floating". A good idea might be to connect it to Vdd via a pull-up resistor of say, 4.7 kOhm.
Imagine what would happen in an "ISR-less" application when you have set bit 5 in the OPTION register by some reason (i.e. RTCC roll-over interrupt enabled), with a floating RTCC input randomly incrementing the RTCC, and finally causing a jump to $000 on a roll over. As your program does not contain any spe-cific ISR code, it might restart, or perform some other crazy operations."

so that is where I got the 4.7k. Though I completely skipped over the reset button area of the schematic when I was looking through it. I'll have to remove the MCLR resistor I put in. I think the RTCC pin should be tied to something.

The jumpers on the 1307 board do enable/disable the 10k resistors built in to the 1307 board and are enabled.

what is happening, is I do get the serial out asking what type of display I want after doing a program(ctrl+p). I choose, and it send the wanted formatted time out. It keeps repeating the time out until it randomly stops. I haven't been able to get it to start without me doing a program with the resonator already plugged in. Looking through the code, it doesn't care if the PC transmits again. I think I've hit keys while it was displaying the time, but not sure. Will have to test.

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