Tom=E1s =D3 h=C9ilidhe wrote: > Anyway here's what went on in my head when I was trying to get a grip > on it: > * Power =3D Energy per second > * Power is measured in watts, which is joules per second > * Power =3D Voltage x Current =3D volts x amperes > * 1 ampere =3D 1 coulomb per second > * Therefore Power =3D volts * coulombs / seconds > * Therefore Energy =3D volts * coulombs This is all correct. > Is it possible to take that 1.5 volts, step it up to 5 volts, and make > it put a steady 25 mA through the resistor? Yes. That's what switching power supplies do, in this case a "boost" converter. Switchers convert watts at one voltage and current to watts at a different voltage and current, minus some loss. > * I haven't a clue how efficient step-up regulators are, but I'll > take a wild guess of 95 %, so that would bring the battery current to > about 87 mA. Unless you're a expert, and you're not if you have to ask, 70-80% is a better estimate. ******************************************************************** Embed Inc, Littleton Massachusetts, http://www.embedinc.com/products (978) 742-9014. Gold level PIC consultants since 2000. -- = http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist