In SX Microcontrollers, SX/B Compiler and SX-Key Tool, tdg8934 wrote:

I was going through the code. See attached program. 
More specifically was the OUT subroutine which replaces the SHIFTOUT routine. 

It clearly shows the R1, R2, G1 and G2 datapins as well as Clock and Latch. However before it used pattern(temp1) to indicate the actual data being shifted. Using this new format, it is unclear how this is to be laid out. I am guessing something like: [b]pattern(temp1) = RB[/b] but really not sure. 

[code]
SUB OUT 


  bitmask = $80 

  

  FOR temp1 = 7 to 0 step -1 

  

  FOR hotdog = 1 to 8 

  

    B_R1 = R1 & bitmask           ' 0 or bitmask
    B_R1 = B_R1 / bitmask         ' 0 or 1
    R1_Dpin = B_R1
    B_R2 = R2 & bitmask           ' 0 or bitmask
    B_R2 = B_R2 / bitmask         ' 0 or 1
    R2_Dpin = B_R2
    B_G1 = G1 & bitmask           ' 0 or bitmask
    B_G1 = B_G1 / bitmask         ' 0 or 1
    G1_Dpin = B_G1
    B_G2 = G2 & bitmask           ' 0 or bitmask
    B_G2 = B_G2 / bitmask         ' 0 or 1
    G2_Dpin = B_G2
    
   ' the RB bits have been set, ready to pulse clock for external latch 


    Pulsout S_Cpin, 2     
           
    bitmask = bitmask / 2     ' 1_$40, 2_$20, 3_$10, 4_$08, 5_$04, 6_$02, 7_$01, 8_XX 

  

  NEXT 

  

  [b]pattern(temp1) = RB[/b]
  
  NEXT 

  

  PULSOUT L_Latch, 2                               ' transfer to outputs 

  

ENDSUB 

 
You will see the FORWARD routine calls out the OUT subroutine which used before 
SHIFTOUT R1_Dpin, S_Clk, MSBFIRST, pattern(temp1)
So where does pattern(temp1) fit into this new routine?

Thanks! [/code]

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