Michael, > When measuring AC power levels the problem is that the AC voltage and > current is varying so the instantainious power delivered (the product > of voltage and current at that instant) is not constant. So it is > convienient to convert the AC readings to an equivelent constant > reading that would deliver the same power over an extended period. > (i.e greater than one cycle). This can be done by taking a large > number of readings over the course of one cycle, multiplying the > current and voltage and iintegrating the result.... Thanks Richard.. That was was one of the most informative emails I have read in a long time. Very helpful:) Mike -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist