> So a linear regulator, like LM1084 which i had in mind, won't work? Ignoring the power drawn by the regulator itself (which is usually very little), the current going into a linear regulator is equal to the current going out of it. So if you draw 5A from the 12V side of the regulator, it will draw 5A from the 18V side and dissipate 6*5=30W. I doubt you want 30W ending up on the regulator heatsink. There is no way around this fact with linear regulators - if you want to minimize the power dissipation of the regulator (6W per amp in your case) and have an input current smaller than the output current, you'll need a switching regulator. -- Hector Martin (hector@marcansoft.com) Public Key: http://www.marcansoft.com/marcan.asc -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist