Hi Jinx:

I'm with you, but for me it's even simpler.

At the time of the first pick the problem is "there are three doors and one of 
them is a winner and the other two are losers, so the odds of a winner are 1 in 3.

At the time of the second pick the problem is "there are two doors and one of 
them is a winner and the other one is a looser, so the odds of a winner are 1 in 2.

There is no memory when it comes to gambling, i.e. what's happened in the past 
has no impact on the current odds.  For example suppose someone who was not in 
the room for the first pick is brought into the game after one of the doors has 
been opened.  They only see the second problem i.e. they are to choose one of 
two doors and only one door has the prize.  The newcomer's odds are 1/2 the 
same as the original contestant at that point.

-- 
Have Fun,

Brooke Clarke
http://www.PRC68.com
http://www.precisionclock.com
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