>>But, radiation and convection may be significant contributors >>depending on a number of factors which may be poorly understood or >>controlled here. > I think they can be ignored for the purpose of getting an estimate = > of the > effect of the T/C under the presumed conditions (< 100=B0C). Why? That may be good advice. But, can you provide rough justification for = it. Holding the leads a small distance away from a hot component with thin = leads will expose you to a much reduced temperature. My intuitive feel is that if you had a small device with thin wires at = approaching 100C then the lead conduction would be smallish but that = if you placed a sensor (finger, tongue or arcane electronics) near but = not touching it that you would sense substantial energy transfer. Leads may be copper or (some may be surprised to find) steel. Copper has a coefficient of thermal conductivity of about 390 W/m/k. = Steel/iron leads will be about 5+ times lower conductivity than that. Watts dissipation by lead heatsinking can be worked out from there. Having copper or steel leads will greatly affect the result. In the case of a thermocouple the leads will usually be neither copper = nor steel. The fact that PTC devices and other thermistors can have their = thermal/resistance characteristics very substantially affected by eg = adding a sleeve of heat shrink indicates that radiation and/or = convection are significant factors. For a black body thermal radiation Wattage =3D Kb x A x T^4 (Kb =3D = 5.7E-8 =3D Boltzmann's constant.) Aaagh :-) Calculator here http://infrared.als.lbl.gov/calculators/bb2001.html Convection ... Aaagh aaagh aagh Now. If you can just tell us the Nusselt number of your thermistor ... = ;-) This is an excellent overview but probably won't help provide = numerical results. http://www.cheresources.com/convection.shtml Russell -- = http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist