> Basically you need to increase the capacitance of the main > cap (the one that is in series with the supply). Use ohms > law but work with the impedance of the capacitor at line > frequency for w=2*PI*f An approximation is I = 6fCV 230V, 50Hz, 1uF, I = 6 * 50 * 0.000001 * 230 = 0.069A 120V, 60Hz, 1uF, I = 6 * 60 * 0.000001 *120 = 0.043A -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist