I used to have a very nice and compact digital soldering station with a = 5W soldering iron that was very good for just about any general SMT or = low-power thru-hole work. Unfortunately, I no longer have with me the = base unit, though I have the actual iron, and I'd like to build a = PIC-powered base unit. While the plug that connects to the base has several pins, only two of = them are connected at the iron side. This particular unit has = closed-loop temperature regulation, so I figure the temperature sensor = and iron are connected together in series. I've heated it up using a hot = air rework station (which claims it was putting out 480=BAC), and measured = a voltage on the two wires. With the rework station, I managed to get it = to output 5-6mV. At room temperature, it puts out 0.1mV or 0.0mV. I'm = guessing it has a thermocouple in series with the heating element. I've never used thermocouples, so I have no clue how I'd go around = measuring the output voltage and amplifying it to a suitable value for a = PIC ADC. I understand thermocouples require a cold junction at the unit = side and compensation for accuracy, though I don't recall seeing a = temperature sensor in the base unit (I took it apart a few times). How = can I tell if the wire from the soldering iron is thermocouple wire or = plain old copper wire? If it's just copper, my guess is the "cold = junction" is formed at the base of the soldering iron. I can't really = take the iron apart without destroying it. I don't need perfect = temperature readout, since after all I just choose a soldering = temperature that works well through trial and error. Consistency would = be nice, however. FWIW, the iron is a JBC 5W model. Here's a diagram of the entire station: http://www.jbc.es/pdf/despieces/md3050.pdf The iron is the "ROD" 5W model. I'm guessing drive voltage would have to be pulsed (it'll end up being = pulsed once it reaches the set temperature anyway, due to the closed = loop), so I would take the temperature measurements between pulses. This = also means the measuring circuit has to withstand whatever voltage I put = across the iron (or somehow get disconnected during that time). Also, if = the time between pulses is short, I'd have to worry about capacitance = skewing results due to the previous high-voltage pulse. Ideas? -- = Hector Martin (hector@marcansoft.com) Public Key: http://www.marcansoft.com/marcan.asc -- = http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist