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This time with the attachment.... ;-)

Sorry. It really was in the first mail, bust have been because it was 
pasted in rather than attached.

Rolf

Rolf wrote:
> Sean Breheny wrote:
>   
>> Hi Rolf,
>>
>> Could you either post or send to me directly your schematic? It sounds
>> like what you are trying to do should work properly. I've never used
>> the MCP6044 but I took a quick look at the datasheet and it looks
>> fine.
>>
>> For future reference, my favorite op-amp for general purpose stuff is
>> the LMC648x (6482 is a dual, 6484 is a quad) from National. It is not
>> cheap (about $5) so it is not a good choice for most inexpensive
>> commercial applications, but for hobbyist one-offs it can't be beat.
>> It is rail to rail input and output, ultra-low input bias current, max
>> 1mV input offset voltage, pretty low noise, 1 MHz gain-bandwidth
>> product. The MCP6044 seems to trade off GBW product for supply current
>> (it has about 1000 times less supply current than the LMC6482 but also
>> almost 100 times slower).
>>
>> Sean
>>
>>
>> On 5/5/07, Rolf <learr@rogers.com> wrote:
>>   
>>     
>
>
> The top is a simple voltage follower. In my case I am getting erroneous 
> output at low input voltages. Specifically, the charger is currently 
> charging at 12.5mA as measured with one DMM. Another DMM measures the 
> output of the charging chip at 12.7mV (pretty close...). The same DMM 
> that measures 12.7mV on the charge chip output (input to the follower), 
> reads 1.5mV on the op-amp output. It should be 12.7!!! If I put a load 
> on the op-amo out (255R to ground), the opamp out measures 2.1mV. Still 
> very wrong.
>
> In the second circuit, I tried to set up a "difference" circuit. The 
> theory is that the output should be (4.5V - input) * (100K/200K). Or, an 
> "Amplified difference" with a 2x gain. I was figuring I could correct 
> the inversion using math on the A/D module.
>
> The problem with the second solution is that the output of the opamp is 
> 'pushing' back against the input signal. Currently the charge signal is 
> 12.3mV (I type slowly, it has charged a little more). But, when I 
> connect it to the op-amp circuit, it rises to 20.2mV, and the out put of 
> the opamp, which I expect to be about 24.6mV less than 4.5V, is actually 
> 2.36V. So, I am confused ;-)
>
>  From the charger's datasheet they make it clear not to load the signal 
> in any way.... and the second circuit obviously messes with it.
>
> My original circuit was circuit 3. A simple gain amplifier with gain of 
> 2. This woks fine for larger values of the input signal.
>
> I am investigating other options and Jinx's negative rail (but I will 
> have to use a different op-amp I think).
>
> Rolf
>   


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