On 5/4/07, Kevin wrote: > Matt Bauman wrote: > > During programming, you have a 8V drop (13V-5V) across a 27k > > resistor, effectively pumping 0.3mA into your VDD rail. As long as > > your circuit pulls more current than that from VDD (and your chip > > does), you'll be okay. > > > > Ah. That's why the resistor has to be larger than a certain value, > otherwise the 13V Vpp voltage would cause the 5V Vcc to rise above the > ~7V max limit, right? Could you try to explain how will be that possible ? Imagine exactly the power supply you have in your application for +5V. thx, -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist