M. Adam Davis wrote: > If the runway is very wide (ie, 50 feet? 100 feet?) and the > photographer low to the ground (5 feet off the ground, 400 feet away) > then the shadows would look very similar to what we see in the photo. Hm... it seems the photographer is higher than the plane: the right side of the plane is higher (check out the wheels). Which means that the angle we're looking at the plane is smaller (measured against the horizontal) than the angle we're looking at the runway. Which means that (use trigonometry) the shadow on the runway should be wider (in the picture) than the original object casting the shadow. Which I don't think it is. So how come -- explained geometrically -- that the shadow on the runway is smaller in the picture than the object casting the shadow? Gerhard -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist