There is one problem you probably didn't feell it on your own skin... :) The current transformer secundar MUST work in short circuit. Else become a high voltage transformer. As high voltage you'll have as big is the transformer ratio. Example: 1KA to 5A transformer gave around 5KV in secondary if it's open and 100A flows in the primary. All the theory below is just theory. Vasile On 3/20/07, Sean Breheny wrote: > Alan, > > I'm pretty sure that he is correct. There is no physical law which > says that the secondary current equals the primary current times the > inverse of the turns ratio. That is an approximation which is valid > for a certain range of load impedances. Fundamentally, you are > producing some changing flux in the secondary. This will produce a > given open-circuit voltage according to Faraday's Law. As you load it > down, and allow current to flow in it, that current will act to reduce > the flux change. As you approach a short-circuit (load impedance much > less than the reactance of the secondary) in the secondary, the > current will begin to match the approximation you mention. > > Sean > > > On 3/20/07, Alan B. Pearce wrote: > > >> Umm, I think you have a problem with mixed units. > > ... > > > > >I am talking about measuring the magnetic field produced by current > > >in a conductor.A voltage will be induced in the terminals of a winding > > >wounded around the toroid when the magnetic flux is changing in time. > > >I will process this induced voltage to the project requirements.That > > >is it.No need to deal with the current coming out of the secondary coil. > > > > Umm, wrong. The magnetic field induces a current in the coil, and the > > voltage you get out of that will depend on what resistor you put across the > > coil. > > > > This resistor will have a temperature co-efficient that will almost > > certainly not meet the accuracy spec you are being asked for. > > > > The various current probes we have around here all suffer from some form of > > temperature drift, and the best ones talk in terms of accuracy of about 2%, > > which is 10^2 worse than you are asking for. > > > > Then as Vasile points out, you will not get a consistent magnetic field in a > > clamp on system. The only way to do that is to thread a wire through a > > permanently closed toroid. The changing air gap will cost you 1-2%, again a > > couple of orders of magnitude worse than you are wanting. > > > > -- > > http://www.piclist.com PIC/SX FAQ & list archive > > View/change your membership options at > > http://mailman.mit.edu/mailman/listinfo/piclist > > > -- > http://www.piclist.com PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist