Hi Orin,

> > 0000d2   9f8a     BCF       0x8a,0x7,0x1
> >
> > 0000d4   478a     RLNCF     0x8a,0x1,0x1
> 
> Ahem, the above clears bit 7 then rotates left with no carry!
> 
> Orin.

Good catch!!! You are so right.  When I stepped through the code in
MPLAB I was looking at the wrong status register bit and missed that.
Shows what happens when I rush.

Interesting though.  The compiler writers chose to use the RLNC by first
clearing bit 7 and then letting that rotate into BIT 0.

I stuck in assembly code that did the opposite
  STATUSbits.C = 0;
  _asm
  RLCF	MorseChar,1,1
  _endasm

Which in the end did exactly the same thing but left the carry with the
msb.  Considering how useful that is I wonder why the authors didn't do
it that way?  Same number of instructions since STATUSbits.C = 0; ==>
BCF	STATUS,0,0

John Dammeyer


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