Yeah i think you are right. I just reread the data sheet and I realized that with the quiescent current that they specify there should be about a 900 ohm resistance between the output 5V and the ground. I had just assumed that there was some sort of diode on those outputs so my multimeter would not have been able to check the resistance of a voltage regulator. thanks, Adam On 3/14/07, peter green wrote: > > > > While I was checking a printed circuit board that I made, I found a > > 900 ohm short between my ground and 5 volts after my low drop out > > regulater. I thought that there was something wrong with my circuit > > until I checked everywhere I could think of. Finally I measured the > > resistance on another working circuit (different design) which I made > > with that same regulator and there was that same 900 ohm resistance. > > > > The LDO is the fix 5V of the LD1117 series, digikey number > 497-1243-1-ND. > > > > Could their have been a flaw in the manufacturing run of my parts or > > is this a fundamental part of low drop out regulators? > measuring resistances in a constructed cuircuit often wont lead to > sensible results, with your metering you will be either applying a voltage > to the output with nothing on the input or worse applying a reverse voltage > to the output, neither of theese are even close to the normal operating mode > of the device. > > if the regulator is behaving itself (within the parameters in the > datasheet) with regards to its specs in terms of input current with no load > i really wouldn't worry about it. > > > -- > http://www.piclist.com PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist