Hi: If I used a Normally Open vibration switch as a PIC input it could be connected between Vcc and the input. A high value resistor between the input and ground would pull down the input and I think the current used would be minimal. But if a Normally Closed vibration switch is used is there a circuit that would not draw current while waiting for vibration? A coin cell will be powering this circuit. This type (2 ball) is much more sensitive to vibration than the spring over rod type that's N.O. See: http://www.pacificsites.com/~brooke/Sensors.shtml#Vibration Have Fun, Brooke Clarke -- w/Java http://www.PRC68.com w/o Java http://www.pacificsites.com/~brooke/PRC68COM.shtml http://www.precisionclock.com -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist