Look in the include file for the definitions of constants like this.

On 3/7/07, Mauricio Jancic <info@janso.com.ar> wrote:
>
> Yes, I knew it was a bit shift, but I didn't understand de PB1 and why was
> shifting PB1 1 time to the left (here you can see my mistake)...
>
> The thing is PB1 is a constant indicating pin number, and it was shifting
> the 1 PB1 times to the left and then ANDing it to PINB.
>
> Just a missreading
>
> THANKS!!
>
> Mauricio
>
>
>
> > -----Original Message-----
> > From: piclist-bounces@mit.edu
> > [mailto:piclist-bounces@mit.edu] On Behalf Of David VanHorn
> > Sent: Tuesday, March 06, 2007 20:43
> > To: Microcontroller discussion list - Public.
> > Subject: Re: [PIC] Quick C question
> >
> > On 3/6/07, Mauricio Jancic <info@janso.com.ar> wrote:
> > >
> > > Hi,
> > >        I modifying a C code for an ATMEL chip, and I found
> > this statement:
> > >
> > > if(!(PINB & (1<<PB1)))
> > >
> > >        Whats that? Specially the (1<<PB1) that I cant seem
> > to figure
> > > out...
> >
> >
> > That's a bit shift, a common way to address individual pins.
> > They are masking the read of PINB against a byte with the PB1 bit set.
> > So, the statement is conditional on gettting a zero on the
> > PB1 bit of PINB.
> > --
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