Yes, I knew it was a bit shift, but I didn't understand de PB1 and why was
shifting PB1 1 time to the left (here you can see my mistake)...

The thing is PB1 is a constant indicating pin number, and it was shifting
the 1 PB1 times to the left and then ANDing it to PINB.

Just a missreading

THANKS!!

Mauricio



> -----Original Message-----
> From: piclist-bounces@mit.edu 
> [mailto:piclist-bounces@mit.edu] On Behalf Of David VanHorn
> Sent: Tuesday, March 06, 2007 20:43
> To: Microcontroller discussion list - Public.
> Subject: Re: [PIC] Quick C question
> 
> On 3/6/07, Mauricio Jancic <info@janso.com.ar> wrote:
> >
> > Hi,
> >        I modifying a C code for an ATMEL chip, and I found 
> this statement:
> >
> > if(!(PINB & (1<<PB1)))
> >
> >        Whats that? Specially the (1<<PB1) that I cant seem 
> to figure 
> > out...
> 
> 
> That's a bit shift, a common way to address individual pins.
> They are masking the read of PINB against a byte with the PB1 bit set.
> So, the statement is conditional on gettting a zero on the 
> PB1 bit of PINB.
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