>
> But by the tenets of Linear Algebra, spanning vectors, etc., there has
> to be. You still have two axes, that's not enough to describe a
> 3-dimensional space.


Yup.  I see that now.  Bummer.
No matter how you twist, there's always a vector that's 90 degrees out from
both of them.

I can email a jpg that shows this, if anyone's interested.
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