I'm working on a 480V distribution relay protection project that requires the application of a shunt trip device at the time of an overload condition. I need to detect when the load exceeds 500A, and at that time apply a short across the 480V source in order to force the circuit's 2000A main breaker to trip. This is similar to using a grounding switch as the initiator for a transfer trip scheme in the electric utility world. Crude, but simple and effective. I have argued for other methods but this method has been dictated by the client, the government client. Detecting the current is no problem. My effort now is to determine the best method to apply the short. The available fault current is in the neighborhood of 50kA. A near-zero ohm short would be ridiculous. A fault current of approximately 3000A is sufficient and it can be limited to that magnitude if I use a 425uH (160mohm) inductor for the shorting conductor. Such an inductor would be roughly 15cm in diameter and 30cm long, with 90 turns of wire that is capable of withstanding the 3000A surge current for a maximum time of about 10 cycles, or 160 ms. The question now is: What is the best way to switch the inductor across the 480V supply? Traditional clapper or mercury wetted relay? Triac? SCRs? Whadayathink? Thanks. M. Peterson The preceding e-mail message (including any attachments) contains information that may be confidential, or constitute non-public information. It is intended only for the designated recipient. If you are not the named addressee, you should not disseminate, distribute or copy this e-mail. If you have received this e-mail by mistake, please notify the sender immediately by replying to this message and delete this e-mail from your system. Use, dissemination, distribution or reproduction of this message by unintended recipients is not authorized and may be unlawful. -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist