Tom,

Previews guy did it by using pic internal ADC. Another problem is
that the design is already done and I can't change it.
Can you explain more detail ?

thanks

Andre


Tom Sefranek wrote:

>Your looking for a 12 bit (11bits actually) A-D.
>Then some bit manipulation. (Math).
>
>Andre Abelian wrote:
>
>  
>
>>Rolf,
>>
>>thanks for your replay. Using Vref is very good idea but in my case the 
>>situation is lot more
>>complicated. This is how it should be:
>>
>>0-2,4v  output 0-1023 with 2's complement format and enable a bit
>>2.6-5.0v  output 0-1023 disable the bit. While it is in between 2,5v 
>>should output 0
>>
>>any idea?
>>
>>thanks for your help
>>
>>Andre
>>
>> 
>>
>>    
>>
>>>Andre Abelian wrote:
>>>
>>>
>>>   
>>>
>>>      
>>>
>>>>Hi to all,
>>>>
>>>>I need to convert ADC 0-2,5v  result to  0-1023 output to uart.
>>>>I am kind of lost how to do this should I add result x 2?
>>>>any help will appreciate.
>>>>
>>>>thanks
>>>>
>>>>Andre
>>>>
>>>>  
>>>>
>>>>     
>>>>
>>>>        
>>>>
>>>You need to get 2.5V on the Vref+ pin, and use that for the 10bit 
>>>conversion. The challenge is then to get a 2.5V reference.... ;-)
>>>
>>>On PIC18 devices see the ADCON1 register bits VCFG0 and VCFG1
>>>
>>>on PIC16's see the ADCON1 register's PCFG bits.
>>>
>>>Rolf
>>>
>>>
>>>   
>>>
>>>      
>>>
>> 
>>
>>    
>>
>
>  
>

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