Jinx wrote: >>7805 is still up around 8-ish volts. Probably need a 2W, you'll >>have work that out from actual current passed. >> >>HUH? You calculated the ENTIRE dissipation is "about 0.5W" >> >> > >Hi Tom, > >Added a margin for wallwarts being notoriously over label voltage, >derating for high ambient, and just plain conservativism. A 1/2W >wire-wound may be OK running at 50C + Tcurrent, but another >sort (eg 1/2W metal film or carbon) may not for extended periods > >If wallwart is actually 12.0V, that's 0.497W for the drop across >the regulator for starters > Hi Jinx, O.K. and if you dissipate about half the heat in a resistor that is what wattage? (Actually about 4/7 of the heat...) Appears to me to be a waste of a 2 watt resistor, and probably a real safe bet for a half watt of ANY composition. In my experience, wall warts are VERY close to their voltage ratings when fully loaded. I suppose if a wall wart had a 35% loss ratio... (It would get pretty warm too...) But out of the hundred or so I do have of various voltages, none of them vary by more than 20%. I guess if your power is like Bonaire (island), you could get primary variations of more than 20%. Still, bonding the regulator to the metal case is a reasonable solution. -- * | __O Thomas C. Sefranek WA1RHP@ARRL.net |_-\<,_ Amateur Radio Operator: WA1RHP (*)/ (*) Bicycle mobile on 145.41, 448.625 MHz http://hamradio.cmcorp.com/inventory/Inventory.html http://www.harvardrepeater.org -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist