>
>>  How does a twisted pair of wires opened at one end charge a
>> capacitor? I have tried that and got nothing.
>
>It's pretty simple, actually.  The twisting provides a series of loops,
>the magnet passes the loops, which causes a change in magnetic
>flux through the area of each loop, which induces a current, which
>flows into the capacitor.  That energy is released from the cap as
>the magnet passes over the larger coil at the bottom.


But it seems that the twisted red and black wires are open
on the opposite side of the capacitor. But I=B4m not sure...
Pay attention in the beginning of the movie.


Regards,

Rubens
PY2RML

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