Good catch there Scott. The price you pay for HLL. You
tend to forget the specifics for an arch*Which I can't
remember all the tiny gold nuggets*.

John


--- Scott Dattalo <scott@dattalo.com> wrote:

> On Tue, 2006-11-14 at 18:07 -0800, Shawn Wilton
> wrote:
> 
> 
> > Does anyone see anything wrong with this code:
> >
> > //Set page 103 for details regarding the +2
> >     tmr0l = (unsigned char)65000;
> >     tmr0h = (unsigned char)(65000 >> 8);  //Right
> shift so the top byte
> > becomes the bottom byte
> 
> Others may or may not be correct about the default
> signedness of
> chars, but I believe your problem is even more
> fundamental. When
> writing to a 16-bit timer, you must write the high
> byte first. The
> write to the low byte will initiate a full 16-bit to
> real
> hardware. Similarly, to read a 16-bit timer, read
> the low byte
> first. This will initiate an access of the high byte
> too which you may
> read on the subsequent instruction.
> 
> Scott
> -- 
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