In SX Microcontrollers, SX/B Compiler and SX-Key Tool, metron9 wrote:

I have been working with assemblers for a long time back to the 6502 days. I have tried to learn the SX but the following three pictures show you why I don't understand it.

Debugger running, three lines of code, pictures are step1, step2, and step3

Step1 shows the register w = F0 = %111000    RA has just been loaded and contains %00001111
That's fine I understand it flips the bits 0=1 and 1=0 why the flipping is necessary is beyond the scope of this post.

Step2 shows:
 
mov M,#f 
MOV w,#0f 
mov !RB,W 

have just been executed now RA changes from %00001111 to %00000000  Why?

Step3 shows

mov !RB,W

Now w is still %01000101 but !RB is now %11111110

---------- End of Message ----------


You can view the post on-line at:
http://forums.parallax.com/forums/default.aspx?f=7&p=1&m=154463

Need assistance? Send an email to the Forum Administrator at forumadmin@parallax.com

The Parallax Forums are powered by dotNetBB Forums, copyright 2002-2006 (http://www.dotNetBB.com)