Russell McMahon wrote:
>> Hopefully it calculates the great circle route which is a curve, not 
>> a
>> "strait" (sic) line.
>>     
>
>
> A great circle route is a straight line (for certain values of 
> straight) on the surface of a spherical projection. But, you knew that 
> :-)
>
>
>         Russell
>
>
>   
Yeah, but it is a curve (for certain definitions of  "curve") any way 
you look at it in Euclidean 3-space which also happens to be a linear 
manifold. ;)

Carey
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