Yeah, I've seen that worthless document. I have the 9V adapter plugged in to the ICD, so I don't think I need to apply an external VDD so long as I set the ICD to power the target (which is unconnected). Should still go ahead and connect. Iff VDD were not powered wouldn't the ICD fail to connect and fail the self-tests as well? On 10/3/06, WH Tan wrote: > > On 10/3/06, Shawn Wilton wrote: > > > How do you tell which pin on the ICD chip is GPIO3? I would think that > > you could use the header outside of your circuit, or that it should at > least > > enter debug mode...? > > With Pin 3 of the 14-pin -ICD device being mapped to pin 1 of the real > F675, then GPIO3 of the real F675 is pin 4, which is should be pin 6 > of the -ICD device. You can have a look at page 7 of DS51292L. > > > > I see there might be some confusion here: At the -ICD device pin 3 - > pin 6 and pin 9 -pin 12 are meant to be mapped to your target > circuit. Since you're using external MCLR/GPIO3 (don't confuse this > one with the Vpp/~ICDMCLR), you have to pull it to Vdd. Aren't all 8 pins supposed to be mapped to the target as the ICD header takes the place of any chip you would otherwise have installed on the board? -- Shawn Wilton (b9 Systems) http://b9Systems.com <- New web page -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist