I think the most efficient approach would be to use motors that are rated for the battery voltage. Failing that, I suspect a bridge switcher driving a transformer is the most efficient way to get a relatively high power to a higher voltage. A typical boost converter (which I consider a form of a "flyback converter") becomes impractical above 100 or 200 watts. Harold > On Sunday 24 September 2006 10:46, Xiaofan Chen wrote: >> What is the requirement for the boost converter? For example, >> the input and output voltage, the efficiency requirement. Depending on >> the requirement, the design will be totally different. > > Input is automotive voltage -- say 10V to 14V. Output is approx 20V, and > the > higher current will be used to power some motors. Efficiency is "as > efficient as possible, within reasonable cost". It's not a portable > battery-powered device, so it does not have to be 99% efficient, yet, > given > the current requirement, I'd like it to be as efficient as possible so > that > there's less heat to be dissipated. I know that's very shady, but I'm not > familiar with the high-current design, so I would evaluate various > efficiencies vs. cost ... that is, IF I have choices. > > >> 50A is not small current. 50A @3V will be 150W. 50A@24V will be >> 1.2kW and the design approach will be very different. >> >> The design which fits 1A@3V will not fit for the design of 50A@3V >> since the loss on the diode will be too much and you may have to use a >> synchronous boost design. > -- > http://www.piclist.com PIC/SX FAQ & list archive > View/change your membership options at > http://mailman.mit.edu/mailman/listinfo/piclist > -- FCC Rules Updated Daily at http://www.hallikainen.com - Advertising opportunities available! -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist