> I'm not familiar with C18, but is a "char" a signed 8-bit 
> quantity or an
> unsigned 8-bit quantity?  It is is signed, you would expect the VC++
> behavior.  If it is unsigned, you would get the C18 behavior.

In ANSI C it is left to the compiler to decide whether a char is signed
or unsigned. So if you want to be sure of anything outside 0..127 you
will have to declare a 'signed char' or 'unsigned char'.

Wouter van Ooijen

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