If you expect "char" to be signed, use "signed char".  C does not
specify whether plain "char" is signed or unsigned.

On Mon, 18 Sep 2006, Kenneth Lumia wrote:

> I am either making a really stupid error, or there
> is a bug in the C18 compiler (PIC18F4620).  I'm attempting
> to cast a variable from 8 bits to 32 bits and it appears that the
> sign is not being properly extended.  Just to really annoy
> me, I tried it in VC++ and it works correctly.  I've
> tracked the "bug" down to the following simplified code:
>
> typedef char INT_8;
> typedef long INT_32;
>
> void main()
> {
>
>    INT_32 offset;
>    INT_8 temp;
>
>
>    temp = -5;
>
>    offset = (INT_32)temp;     //VC++ correctly reports 0xffff fffb
>                                               //C18 reports 0x0000 00fb
>
> }
>
> Is it me or the compiler?
>
> Thanks,
>
> Ken
> ________________________________________
> "Well that never happened in any of the simulations"
> klumia@adelphia.net
>
> -- 
> http://www.piclist.com PIC/SX FAQ & list archive
> View/change your membership options at
> http://mailman.mit.edu/mailman/listinfo/piclist
>

--
John W. Temples, III
-- 
http://www.piclist.com PIC/SX FAQ & list archive
View/change your membership options at
http://mailman.mit.edu/mailman/listinfo/piclist