In SX Microcontrollers, SX/B Compiler and SX-Key Tool, Rsadeika wrote:

Thanks Bean,

So, if I use a 9600 baud selection, the B9600 con 8 would be B9600 con 4, which would be the same value as the original B19K2 con, so that should do the trick, right? And, I guess I would have to change tht BitTm, and BitTm15 values to the new baud rate. I guess in these types of examples it would be nice if their were two, one at one baud rate, and the other at a different baud rate. That way I guess one could look at the code and see what is changing at the different baud rates, and in the end learn some general concepts about serial coding.

Thanks

Ray

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