On Monday 24 July 2006 12:30, Vasile Surducan wrote:
> Assuming the whole voltage is contributing to the output power (no
> lost on Vce or Vds, no lost on the emiter resistor, with load in the
> collector) then:
>
> 1. Po = Vcc * I   where Po = power, Vcc= supply, I = load current
> 2. from the Ohm law  I = Vcc/Zo
> taking Zo from eq2.  and replacing in eq 1. will result  Zo = Vcc^2 / Po

My understanding from this derivation is,
To use this method, we need to first finalize how much output power we
need Po. Then the formula is used to match load RL to Zo  inorder to 
deliver 'required'  power Po to load. 
Matching is not done for 'Maximum' Power Transfer. 
am i correct ?

so in amplifier , impedance matching is done to deliver required power output
to load , not maximum power to the load ?

regards,
palani



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