> There is another possibility, what if I use two 2N3906's (see attachment)?
> Any reason why it wouldn't work? I haven't had a chance to breadboard it
> yet.
>
> The CE drop is about 0.2V, which is acceptable. Worst case for 7805 is
> 4.75V, worst case for BOR is 4.52V, therefore acceptable voltage drop is
> 4.75 - 4.52 = 0.23V.

This of course did not work in practice (current goes C->E as well as E-C).

Any other suggestions? There's got to be a way to do this..

Best regards,

Vitaliy 

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