> I worked thru the equations of getting > power from pure drag, and if I didn't mess up it shows that > maximum power from an object moving downwind results from the > object's speed being 1/3 the wind speed. If you apply this > to the wind power equation for a square flat plate > (coefficient of drag about 1.17), then you get about 17% > efficiency (again if I didn't mess up). That is the power > that can be taken from a square flat plate being pushed > downwind compared to the total power in the wind. The 1.17 > figure assumes a square flat plate in free air, meaning the > air flows around all sides and only truly stalls in the > center. This coefficient of drag can be higher if air can be > prevented from flowing around all sides giving a larger stall > or near-stall area as is possible with my design. I would love to see how you made that calculation. I don't question it, I'm just curious how you calculated it. > > I don't know how 17% compares to other wind turbine designs > or the theoretical maximum that can be taken from wind (there > is a sort of Carnot efficiency for wind, you can never get it all). I've been told that the maximum theoretical efficiency of a windmill is 35%. No idea how that was calculated, but it is just about twice what you came up with so I wonder if there is a doubling going into their calculation. > Also as you noted, efficiency in terms of fraction of energy > removed from the wind isn't the point anyway for small scale > use. Efficiency in watts/$ is more relevant, including $ for > maintenance. Absolutely. And different designs may be better matches to different situations. > As for the airplane analogy, that doesn't make any sense. > Airplanes are trying to accomplish different things. For one > thing drag is very important because it directly counters > thrust and therefore reduces efficiency. > However for a wind turbine, much of the drag only results in > greater forces on a bearing. This increases cost, but has > nothing to do with energy conversion efficiency. The amount of air that is acted upon by a wing is greater than that of a flat plate. This allows the same size device to act as if it were larger. Or at least that is how I understood it. I have no real knowledge in this area. --- James. -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist