Paul,
aparently, is does a loop decrementing dx, but how fast is your computer?

download http://www.emu8086.com/
is a free emulator.
Regards,

Dennis Crawley
Argnetina

Paul James E. <jamesp@intertex.net> wrote:
> All,
> 
>  If there are any x86 programmers out there that are familiar with
>  assembly language, I would appreciate you having a look at my delay
>  routine and see if you see any obvious reason why it wouldn't work.
> 
>  If I use debug, it seems to work fine.   But if I try to let it run
>  stand alone, it prints one 16 bit value on the screen, and then
> hangs. 
> 
>  I don't understand why it isn't working.   If anyone can help, I'd
>  appreciate it very much.
> 
>  Please advise off line to jim@jpes.com
> 
> 
>                                                  Thanks and Regards,
> 
>                                                         Jim
> 
> ;    RTC.asm    print hardware timer values
> 
>      org 100h
>      push bp
>      stosb
> l1:
>      call near time_delay ; Here is where I call the delay routine
> below.
>      call near time_delay ; I called it three times to see if I could
> notice a delay
>      call near time_delay ; a little better.  But I see no difference
> between one time and three times.
>      mov dx,14ch ;lo
>      in al,dx
>      mov cl,al
>      mov dx,14dh ;hi
>      in al,dx
>      call near putc ;print
>      mov al,cl
>      call near putc
>      mov ax,120h ;' '
>      mov dx,0
>      int 14h
>      jmp near l1
> 
> putc:
>      and al,0fh
>      or al,30h
>      mov ah,1
>      mov dx,0
>      int 14h
>      mov ah,0eh
>      int 10h
>      ret
> 
> =======================  ; Here is the routine I'm interested in
> having evaluated
> 
> time_delay:
>      mov dx,0xffff
> loop1:
>      dec dx
>      cmp dx, 0
>      jnz loop1
>      ret



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