At 05:46 PM 12/1/2005 -0500, you wrote: > > > Of > > > course at 3.3V, you can't get the 25mA you can get at 5V, but > > > that's not > > > the USART's problem. > > > > Eh!? Where does it say that on the datasheet!? > > Why of course? > >Because the output device is a FET, AKA a resistor. > >Output current into any resistive load will always be lower, with lower >VCC. Draw enough current and it no longer acts much like a resistor and becomes a (crummy) current source (once the output drop exceeds Vth, approximately). This may be within abs. max. current specifications at lower supply voltages. >Best regards, Spehro Pefhany --"it's the network..." "The Journey is the reward" speff@interlog.com Info for manufacturers: http://www.trexon.com Embedded software/hardware/analog Info for designers: http://www.speff.com ->> Inexpensive test equipment & parts http://search.ebay.com/_W0QQsassZspeff -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist