Vitaliy wrote: > Gerhard Fiedler wrote: >> 5000 mW / (1609 m)^2 = 1.9 uW/m^2 > > [...] and both times it was you who pointed out the mistake. ;-D I wish I could have contributed something more substantial :) > What you are saying about field strengths makes perfect sense, but I > guess in this particular case I was only interested in the ratio. Jose > Da Silva said: > >> Your 100mW may still be overshadowed by a transmitter a mile away >> pumping out 5W.... > > Which is obviously wrong, assuming the same radiation pattern for both > antennas a transmitter one mile away would have to output 2.6 kW to > match the signal of the local 0.1 W transmitter (Gerhard, let me know if > my calculations are wrong again ;) Not really :) Just adding that you could factor in that the "other" antenna is highly directional and yours is isotropic; then the 2.6 kW could go down by the ratio between their and your antenna. Howard mentioned that there are antennas with a gain of 12, and possibly it could be even higher. So a transmitter with 216 W or less could do it -- and, depending on the application, it also may not be a full mile away. Bringing that together it seems that in the end you could get in trouble with a 5 W transmitter, with a highly directional antenna, 250 m away... (assuming that same RF power means trouble, which I don't know whether it does). Gerhard -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist