On Sun, 27 Nov 2005 09:56:28 -0200, Gerhard Fiedler wrote: > Vitaliy wrote: > > >> Your 100mW may still be overshadowed by a transmitter a mile away > >> pumping out 5W.... > > > > Wow, you are right! I should have done my homework... this goes against my > > intuition: > > > > 100 mW / (10 m)^2 = 1 mW/m^2 > > 5000 mW / (1609 m)^2 = 1.9 mW/m^2 > > Maybe your intuition wasn't that wrong, after all... Probably when you > divided 5000 by 2588881 (that's 1609^2), you took the 10^-3 of the result > as meaning "milli", but with milli already going in, it's "micro": > > 5000 mW / (1609 m)^2 = 1.9 uW/m^2 Hang on, chaps! While the ratio of field strengths in the above calculation is correct (1 : 0.0019) it's wrong to give them a dimension - the actual field strengths certainly won't be the figures shown above. If you assume an antenna with no gain (isotropic, giving a perfectly spherical radiation pattern) field strength of 100mW at 10m will be about 0.079 mW/m^2 (calculated using the area of a sphere, 4 pi r^2). Now isotropic antennae are kept in the same drawer as frictionless pulleys and light, inextensible string - they are theoretical only, but a practical antenna for the appication under discussion is unlikely to have a gain over isotropic of more than about 2 or 3. You'd need a highly directional antenna with a gain of about 12 to get 1 mW/m^2, and it's very unlikely that that's what would be used in this case. Cheers, Howard Winter St.Albans, England -- http://www.piclist.com PIC/SX FAQ & list archive View/change your membership options at http://mailman.mit.edu/mailman/listinfo/piclist